If T is time period of simple pendulum at a place where acceleration due to gravity is g,then length of pendulum is

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Transcript

00:00Question says if t is time period of simple pendulum at a place where acceleration due

00:13to gravity is g then length of pendulum is a. gt square upon 4 pi square b. gt upon 4

00:24pi square c 4 pi square upon gt square d 4 pi upon gt square is time period of simple

00:37pendulum is calculated by using formula t is equal to 2 pi under root l upon g. so we

00:49have to find length so to remove square root squaring on both sides so the square on t

01:01is t square the square of 2 pi is 4 pi square and under root will get cancelled with square

01:12so it will be l upon g so we have to find the equation of l so here g is dividing on

01:21the other side of equal it will multiply with time period so it will be g into t square

01:28is equal to 4 pi square into length or by changing sides we can also write it as 4 pi

01:42square l is equal to gt square here 4 pi square is multiplying with l on the other side of equal

01:51it will divide so length will be obtained as gt square upon 4 pi square so the correct option

02:03will be a gt square upon 4 pi square.